3.1025 \(\int (a+b x)^2 (A+B x) (d+e x) \, dx\)

Optimal. Leaf size=75 \[ \frac {(a+b x)^4 (-2 a B e+A b e+b B d)}{4 b^3}+\frac {(a+b x)^3 (A b-a B) (b d-a e)}{3 b^3}+\frac {B e (a+b x)^5}{5 b^3} \]

[Out]

1/3*(A*b-B*a)*(-a*e+b*d)*(b*x+a)^3/b^3+1/4*(A*b*e-2*B*a*e+B*b*d)*(b*x+a)^4/b^3+1/5*B*e*(b*x+a)^5/b^3

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Rubi [A]  time = 0.07, antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {77} \[ \frac {(a+b x)^4 (-2 a B e+A b e+b B d)}{4 b^3}+\frac {(a+b x)^3 (A b-a B) (b d-a e)}{3 b^3}+\frac {B e (a+b x)^5}{5 b^3} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2*(A + B*x)*(d + e*x),x]

[Out]

((A*b - a*B)*(b*d - a*e)*(a + b*x)^3)/(3*b^3) + ((b*B*d + A*b*e - 2*a*B*e)*(a + b*x)^4)/(4*b^3) + (B*e*(a + b*
x)^5)/(5*b^3)

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int (a+b x)^2 (A+B x) (d+e x) \, dx &=\int \left (\frac {(A b-a B) (b d-a e) (a+b x)^2}{b^2}+\frac {(b B d+A b e-2 a B e) (a+b x)^3}{b^2}+\frac {B e (a+b x)^4}{b^2}\right ) \, dx\\ &=\frac {(A b-a B) (b d-a e) (a+b x)^3}{3 b^3}+\frac {(b B d+A b e-2 a B e) (a+b x)^4}{4 b^3}+\frac {B e (a+b x)^5}{5 b^3}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 96, normalized size = 1.28 \[ \frac {1}{3} x^3 \left (a^2 B e+2 a A b e+2 a b B d+A b^2 d\right )+a^2 A d x+\frac {1}{4} b x^4 (2 a B e+A b e+b B d)+\frac {1}{2} a x^2 (a A e+a B d+2 A b d)+\frac {1}{5} b^2 B e x^5 \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2*(A + B*x)*(d + e*x),x]

[Out]

a^2*A*d*x + (a*(2*A*b*d + a*B*d + a*A*e)*x^2)/2 + ((A*b^2*d + 2*a*b*B*d + 2*a*A*b*e + a^2*B*e)*x^3)/3 + (b*(b*
B*d + A*b*e + 2*a*B*e)*x^4)/4 + (b^2*B*e*x^5)/5

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fricas [A]  time = 0.95, size = 113, normalized size = 1.51 \[ \frac {1}{5} x^{5} e b^{2} B + \frac {1}{4} x^{4} d b^{2} B + \frac {1}{2} x^{4} e b a B + \frac {1}{4} x^{4} e b^{2} A + \frac {2}{3} x^{3} d b a B + \frac {1}{3} x^{3} e a^{2} B + \frac {1}{3} x^{3} d b^{2} A + \frac {2}{3} x^{3} e b a A + \frac {1}{2} x^{2} d a^{2} B + x^{2} d b a A + \frac {1}{2} x^{2} e a^{2} A + x d a^{2} A \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="fricas")

[Out]

1/5*x^5*e*b^2*B + 1/4*x^4*d*b^2*B + 1/2*x^4*e*b*a*B + 1/4*x^4*e*b^2*A + 2/3*x^3*d*b*a*B + 1/3*x^3*e*a^2*B + 1/
3*x^3*d*b^2*A + 2/3*x^3*e*b*a*A + 1/2*x^2*d*a^2*B + x^2*d*b*a*A + 1/2*x^2*e*a^2*A + x*d*a^2*A

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giac [A]  time = 1.19, size = 119, normalized size = 1.59 \[ \frac {1}{5} \, B b^{2} x^{5} e + \frac {1}{4} \, B b^{2} d x^{4} + \frac {1}{2} \, B a b x^{4} e + \frac {1}{4} \, A b^{2} x^{4} e + \frac {2}{3} \, B a b d x^{3} + \frac {1}{3} \, A b^{2} d x^{3} + \frac {1}{3} \, B a^{2} x^{3} e + \frac {2}{3} \, A a b x^{3} e + \frac {1}{2} \, B a^{2} d x^{2} + A a b d x^{2} + \frac {1}{2} \, A a^{2} x^{2} e + A a^{2} d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="giac")

[Out]

1/5*B*b^2*x^5*e + 1/4*B*b^2*d*x^4 + 1/2*B*a*b*x^4*e + 1/4*A*b^2*x^4*e + 2/3*B*a*b*d*x^3 + 1/3*A*b^2*d*x^3 + 1/
3*B*a^2*x^3*e + 2/3*A*a*b*x^3*e + 1/2*B*a^2*d*x^2 + A*a*b*d*x^2 + 1/2*A*a^2*x^2*e + A*a^2*d*x

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maple [A]  time = 0.00, size = 101, normalized size = 1.35 \[ \frac {B \,b^{2} e \,x^{5}}{5}+A \,a^{2} d x +\frac {\left (B \,b^{2} d +\left (A \,b^{2}+2 B a b \right ) e \right ) x^{4}}{4}+\frac {\left (\left (A \,b^{2}+2 B a b \right ) d +\left (2 A a b +B \,a^{2}\right ) e \right ) x^{3}}{3}+\frac {\left (A \,a^{2} e +\left (2 A a b +B \,a^{2}\right ) d \right ) x^{2}}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2*(B*x+A)*(e*x+d),x)

[Out]

1/5*b^2*B*e*x^5+1/4*((A*b^2+2*B*a*b)*e+b^2*B*d)*x^4+1/3*((2*A*a*b+B*a^2)*e+(A*b^2+2*B*a*b)*d)*x^3+1/2*(a^2*A*e
+(2*A*a*b+B*a^2)*d)*x^2+a^2*A*d*x

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maxima [A]  time = 0.57, size = 100, normalized size = 1.33 \[ \frac {1}{5} \, B b^{2} e x^{5} + A a^{2} d x + \frac {1}{4} \, {\left (B b^{2} d + {\left (2 \, B a b + A b^{2}\right )} e\right )} x^{4} + \frac {1}{3} \, {\left ({\left (2 \, B a b + A b^{2}\right )} d + {\left (B a^{2} + 2 \, A a b\right )} e\right )} x^{3} + \frac {1}{2} \, {\left (A a^{2} e + {\left (B a^{2} + 2 \, A a b\right )} d\right )} x^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="maxima")

[Out]

1/5*B*b^2*e*x^5 + A*a^2*d*x + 1/4*(B*b^2*d + (2*B*a*b + A*b^2)*e)*x^4 + 1/3*((2*B*a*b + A*b^2)*d + (B*a^2 + 2*
A*a*b)*e)*x^3 + 1/2*(A*a^2*e + (B*a^2 + 2*A*a*b)*d)*x^2

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mupad [B]  time = 0.05, size = 98, normalized size = 1.31 \[ x^3\,\left (\frac {A\,b^2\,d}{3}+\frac {B\,a^2\,e}{3}+\frac {2\,A\,a\,b\,e}{3}+\frac {2\,B\,a\,b\,d}{3}\right )+x^2\,\left (\frac {A\,a^2\,e}{2}+\frac {B\,a^2\,d}{2}+A\,a\,b\,d\right )+x^4\,\left (\frac {A\,b^2\,e}{4}+\frac {B\,b^2\,d}{4}+\frac {B\,a\,b\,e}{2}\right )+A\,a^2\,d\,x+\frac {B\,b^2\,e\,x^5}{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*x)*(a + b*x)^2*(d + e*x),x)

[Out]

x^3*((A*b^2*d)/3 + (B*a^2*e)/3 + (2*A*a*b*e)/3 + (2*B*a*b*d)/3) + x^2*((A*a^2*e)/2 + (B*a^2*d)/2 + A*a*b*d) +
x^4*((A*b^2*e)/4 + (B*b^2*d)/4 + (B*a*b*e)/2) + A*a^2*d*x + (B*b^2*e*x^5)/5

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sympy [A]  time = 0.08, size = 116, normalized size = 1.55 \[ A a^{2} d x + \frac {B b^{2} e x^{5}}{5} + x^{4} \left (\frac {A b^{2} e}{4} + \frac {B a b e}{2} + \frac {B b^{2} d}{4}\right ) + x^{3} \left (\frac {2 A a b e}{3} + \frac {A b^{2} d}{3} + \frac {B a^{2} e}{3} + \frac {2 B a b d}{3}\right ) + x^{2} \left (\frac {A a^{2} e}{2} + A a b d + \frac {B a^{2} d}{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2*(B*x+A)*(e*x+d),x)

[Out]

A*a**2*d*x + B*b**2*e*x**5/5 + x**4*(A*b**2*e/4 + B*a*b*e/2 + B*b**2*d/4) + x**3*(2*A*a*b*e/3 + A*b**2*d/3 + B
*a**2*e/3 + 2*B*a*b*d/3) + x**2*(A*a**2*e/2 + A*a*b*d + B*a**2*d/2)

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